JEE Mathematics • Official PYQs

Complex Numbers & Quadratic Equations

Practice official JEE Main Complex Numbers PYQs online. Master cube roots of unity (omega), De Moivre’s theorem, locus & geometry with step-by-step solutions.

📝 15 Solved PYQs
📅 Exam Years: 2019–2024
📊 Weightage: 4%–6% (1–2 Questions per shift)
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🎯 High-Yield Syllabus Breakdown

These high-frequency concepts account for over 90% of all questions asked in Complex Numbers & Quadratic Equations:

⚡ Essential Formulas & Speed Shortcuts

Formulas and time-saving shortcuts to solve Complex Numbers questions in under 45 seconds:

Speed Trick #1:

Cube roots of unity: 1 + ω + ω² = 0 and ω³ = 1; (1 - ω)(1 - ω²) = 3.

Speed Trick #2:

Triangle Inequality: ||z₁| - |z₂|| ≤ |z₁ ± z₂| ≤ |z₁| + |z₂|.

Speed Trick #3:

Locus |z - z₁| / |z - z₂| = k: Straight line if k = 1 (perpendicular bisector), Circle (Circle of Apollonius) if k ≠ 1.

📖 Sample Solved Exam Questions

Preview authentic questions from this chapter with full step-by-step solutions:

Question 1 of 3 JEE Main 2024 (Online) 27th Jan Shift-1
If z = x + iy is a complex number such that |z - 1| = |z + i|, then the locus of z represents a line with slope:
(A) -1
(B) 1
(C) 0
(D) Undefined
💡 View Step-by-Step Solution & Answer

Correct Answer: -1

  1. Step 1: Given |z - 1| = |z + i|. This geometrically represents the perpendicular bisector of the line segment joining (1, 0) and (0, -1).
  2. Step 2: Algebraically, |(x - 1) + iy|² = |x + i(y + 1)|².
  3. Step 3: Expand: (x - 1)² + y² = x² + (y + 1)² ⇒ x² - 2x + 1 + y² = x² + y² + 2y + 1.
  4. Step 4: Cancel common terms: -2x = 2y ⇒ y = -x. The line is y = -x, which has slope m = -1.

⚡ Speed Tip: Geometric Shortcut: The segment joining (1, 0) and (0, -1) has slope (-1 - 0)/(0 - 1) = 1. Its perpendicular bisector has slope -1/1 = -1.

Question 2 of 3 JEE Main 2023 (Online) 24th Jan Shift-1
If z is a complex number satisfying |z - 3 - 4i| ≤ 2, then the minimum and maximum values of |z| are respectively:
(A) 3 and 7
(B) 2 and 6
(C) 1 and 5
(D) 4 and 8
💡 View Step-by-Step Solution & Answer

Correct Answer: 3 and 7

  1. Step 1: The condition |z - (3 + 4i)| ≤ 2 represents a circular disc with center z₀ = 3 + 4i and radius r = 2.
  2. Step 2: The distance of the center from the origin is |z₀| = √(3² + 4²) = 5.
  3. Step 3: By the triangle inequality, the minimum distance from the origin is |z₀| - r = 5 - 2 = 3.
  4. Step 4: The maximum distance from the origin is |z₀| + r = 5 + 2 = 7.

⚡ Speed Tip: Circle Distance Formula: For |z - z₀| ≤ r, |z|_min = |z₀| - r and |z|_max = |z₀| + r.

Question 3 of 3 JEE Main 2024 (Online) 29th Jan Shift-2
If ω is a non-real complex cube root of unity, then the value of (1 - ω + ω²)⁵ + (1 + ω - ω²)⁵ is:
(A) 32
(B) -32
(C) 16
(D) -16
💡 View Step-by-Step Solution & Answer

Correct Answer: 32

  1. Step 1: Recall the fundamental cube roots identity: 1 + ω + ω² = 0.
  2. Step 2: Therefore, 1 + ω² = -ω, which implies (1 - ω + ω²) = (-ω - ω) = -2ω.
  3. Step 3: Also, 1 + ω = -ω², which implies (1 + ω - ω²) = (-ω² - ω²) = -2ω².
  4. Step 4: The expression becomes (-2ω)⁵ + (-2ω²)⁵ = -32(ω⁵ + ω¹⁰) = -32(ω² + ω) = -32(-1) = 32.

⚡ Speed Tip: Cube Root Substitution: Replace 1 + ω² with -ω and 1 + ω with -ω². The sum collapses into -32(ω² + ω) = 32.

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❓ Frequently Asked Questions (FAQs)

How to solve cube roots of unity problems quickly?

Express quadratic expressions like x² + x + 1 = 0 roots as ω and ω², then use ω³ = 1 to reduce high powers.

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