SSC CGL Quant • Official PYQs

Time, Work & Pipes and Cisterns

Practice 290+ official SSC CGL Time, Work & Pipes PYQs online. Total work LCM method, efficiency ratios, alternate day work & step-by-step solutions.

📝 292 Solved PYQs
📅 Exam Years: 2019–2024
📊 Weightage: 8%–12% (2–3 Questions in Tier 1)
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🎯 High-Yield Syllabus Breakdown

These high-frequency concepts account for over 90% of all questions asked in Time, Work & Pipes and Cisterns:

⚡ Essential Formulas & Speed Shortcuts

Formulas and time-saving shortcuts to solve Time & Work questions in under 45 seconds:

Speed Trick #1:

Chain Rule: (M₁ × D₁ × H₁) / W₁ = (M₂ × D₂ × H₂) / W₂.

Speed Trick #2:

Two person working together: Time = (A × B) / (A + B).

Speed Trick #3:

Efficiency is inversely proportional to time taken: Eff₁ / Eff₂ = Time₂ / Time₁.

📖 Sample Solved Exam Questions

Preview authentic questions from this chapter with full step-by-step solutions:

Question 1 of 3 SSC CGL Prelim Exam. 2016
36 men together can build a wall 140 m long in 21 days; the number, of men work- ing at the same rate required to build the same wall in 14 days is
(A) 54
(B) 48
(C) 36
(D) 18
💡 View Step-by-Step Solution & Answer

Correct Answer: 54

  1. Step 1: Understand problem conditions and equations.
  2. Step 2: Here, W1 = W2 = 140 MM DD W MD W MD M M 12/12 1/11 2/22 2 2/36 21/14 140/36 21/140 14 3 == == = ⇒ × = × ⇒ ,? , ∵ 662 1/14 54× =
  3. Step 3: Evaluating gives verified answer: 54.

⚡ Speed Tip: Verify intermediate calculations and units.

Question 2 of 3 SSC CHSL (10+2) LDC, DEO & PA/SA Exam, 2015
If 20 women can lay a road of length 100 m in. 10 days. Then 10 women can lay the same road of length 50 m in
(A) 20 days
(B) 15 days
(C) 5 days
(D) 10 days
💡 View Step-by-Step Solution & Answer

Correct Answer: 10 days

  1. Step 1: Understand problem conditions and equations.
  2. Step 2: Women 20/100 10/10 50 x Days Length ∴ 10/20 100/50 10: : :: :⎫ ⎬ ⎭ x ⇒ 10/100 20/50 10×× =× ×x ⇒ x = ×× =20/50 10/1000 10 days
  3. Step 3: Evaluating gives verified answer: 10 days.

⚡ Speed Tip: Verify intermediate calculations and units.

Question 3 of 3 SSC CHSL (10+2
A, B and C can complete a piece of work in 24, 5 and 12 days respectively. W orking together, they will complete the same work in
(A) 7/24 days
(B) 3 1/13 days
(C) 4 days
(D) 1/24 days
💡 View Step-by-Step Solution & Answer

Correct Answer: 3 1/13 days

  1. Step 1: Understand problem conditions and equations.
  2. Step 2: A’s 1 day work = 1/24 B’s 1 day work = 1 5 C’s 1 day work = 1/12 ∴ (A + B + C)’s 1 day work =+ +1/24 1 5 1/12 = ++52/41 0/120 ==39/120 13/40 ∴ Required time ==40/13 3 1/13
  3. Step 3: Evaluating gives verified answer: 3 1/13 days.

⚡ Speed Tip: Verify intermediate calculations and units.

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❓ Frequently Asked Questions (FAQs)

How does the LCM method solve Time & Work in 15 seconds?

Assume Total Work = LCM of given days. Divide work by days to get daily unit efficiency. Sum efficiencies and divide total work.

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